How do you solve $sec x = - 5$ $sec x = -5$ ?

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Answer 1 · 2016-11-28T00:52:13

$sec x = - 5$ $secx=-5$

Rewrite left side in terms of cosine:
$\frac{1}{cos x} = - 5$ $1/cosx=-5$

Rewrite right side as $\frac{1}{\frac{1}{- 5}}$ $1/(1/-5)$
$\frac{1}{cos x} = \frac{1}{\frac{1}{- 5}}$ $1/cosx=1/(1/(-5))$

$cos x = - \frac{1}{5}$ $cosx=-1/5$
$x \approx 1.772$ $x approx 1.772$ radians

How do you solve sec x = -5secx=−5sec x = -5?