How do you solve the compound inequalities $4 p + 1 > - 11$ $4p + 1 > −11$ or $6 p + 3 < 39$ $6p + 3 < 39$ ?

Question

5594 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-30T20:35:41

$p > - 3$ $pgt-3$ or $p < 6$ $plt6$

In both instances, we want to isolate the variable. Let's start with our first inequality

$4 p + 1 > - 11$ $4p+1> -11$

Let's start by subtracting $1$ $1$ from both sides to get

$4 p > - 12$ $4p> -12$

Lastly, we divide both sides by $4$ $4$ to get

$p > - 3$ $p> -3$

Now, let's tackle the second inequality

$6 p + 3 < 39$ $6p+3lt39$

Let's subtract $3$ $3$ from both sides to get

$6 p < 36$ $6plt36$

Lastly, we can divide both sides by $6$ $6$ to get

$p < 6$ $plt6$

Therefore, the solutions of this inequality are

$p > - 3$ $pgt-3$ or $p < 6$ $plt6$

Hope this helps!

How do you solve the compound inequalities 4p + 1 > −114p+1>−114p + 1 > −11 or 6p + 3 < 396p+3<396p + 3 < 39?