How do you solve the equation: #-32y^2-24y=0#?
1 Answer
Jun 28, 2015
The solutions are:
Explanation:
Equating the terms with zero to obtain the solution:
-
#-8y = 0 #
#color(blue)(y=0# -
#4y + 3 = 0#
# color(blue)(y = -3/4#