How do you solve the equation: $-42z^2=14z$ ?

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Answer 1 · 2015-06-28T07:23:27

The solutions are:
$color(blue)(z=0 , z=-1/3$

$-42z^2 =14z$

$14z + 42z^2 =0$

Here $color(green)(7z)$ is common to both terms:
$=(7z)(2 + 6z)=0$

Equating the terms with zero to obtain the solution

How do you solve the equation: -42z^2=14z-42z^2=14z?