How do you solve the equation x^2 - 4x = 4? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Tom May 10, 2015 x^2-4x=4 =>x^2-4x+4=8 a = x b = 2 a^2-2ab+b^2 = (a-b)^2 (x-2)^2=8 x-2 = sqrt(8) or -sqrt(8) x_1 = sqrt(8)+2 x_2= -sqrt(8)+2 Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 2347 views around the world You can reuse this answer Creative Commons License