How do you solve the inequality $3a ≤ - 2 - 3a$ or $3a > 2 - a$ ?

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Answer 1 · 2018-04-11T13:01:43

Please look below.

The first inequality can be solved by adding $3a$ then dividing by $6$ :

$3a <= -2-3a$

$6a <= -2$

$a <= - 1/3$

The second inequality can be solved by adding $a$ then dividing
by $4$ :

$3a >2-a$

$4a > 2$

$a > 1/2$

From these two inequalities we get:

$a<=-1/3$ , $1/2 < a$

How do you solve the inequality 3a ≤ - 2 - 3a3a ≤ - 2 - 3a or 3a > 2 - a 3a > 2 - a?