How do you solve the inequality $- 8 < 2 (x + 3)$ $-8 < 2(x+3)$ and $2 (x + 3) < 8$ $2(x+3) <8$ ?

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Answer 1 · 2018-03-16T12:54:59

$- 7 < x < 1$ $-7<x<1$

$- 8 < 2 x + 6 < 8$ $-8<2x+6<8$ combine them and distribute
$- 14 < 2 x < 2$ $-14<2x<2$ subtract 6
$- 7 < x < 1$ $-7<x<1$ divide by 2

How do you solve the inequality −8<2(x+3)-8 < 2(x+3) and 2(x+3)<82(x+3) <8?