How do you solve the inequality #abs(x-3)<8#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Binayaka C. May 24, 2017 Solution: # -5 < x <11 # . In interval notation : #(-5 , 11)# Explanation: #| x- 3 | < 8 or x -3 < 8 or x < 11# OR #| x- 3 | < 8 or x -3 > -8 or x > - 5# Solution: # -5 < x <11 # . In interval notation: #(-5 , 11)# [Ans] Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 2792 views around the world You can reuse this answer Creative Commons License