How do you solve the inequality $x + 5 ≥ 2x + 1$ and $-4x <-8$ ?

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Answer 1 · 2016-02-18T04:18:15

I will solve the first inequality for you and leave the other for you to practice your newfound skill with.

$x + 4 ≥ 2x + 1$

$x - 2x ≥ 1 - 4$

With in equations, always remember that when you multiply or divide by a negative number, you must switch the inequality sign's direction.

$-x ≥ -3$

$x ≤ 3$

Here is the graph of the inequality on a number http://line.

Practice exercises

a) $2x + 6 ≤ -4x - 4$

b) $-3(-2 + 4x) > (2x + 5)/6$

Good luck!

How do you solve the inequality x + 5 ≥ 2x + 1 x + 5 ≥ 2x + 1 and -4x <-8-4x <-8 ?