Question

How do you solve the system `x = 5 - y` and `3y = 3x + 1` by substitution?

Answer 1

We can substitute the `x` of the first equation into the second:

`->3y=3*(5-y)+1`
`->3y=15-3y+1`
`->6y=16->y=16/6=8/3`

Now plug that into the first equation:
`x=5-8/3 =15/3-8/3=7/3`

So `x=7/3 and y=8/3`

Check your answer with the second equation:

`3* 8/3 = 3* 7/3 +1 ?-> 8=7+1` Check!