How do you solve the system y= 6x - 11 y=6x−11 and -2x - 3y = -7−2x−3y=−7 by substitution?

1 Answer
Alan P.
Jun 3, 2015

Given
"[1] "y = 6x-11[1] y=6x−11
"[2] "-2x-3y = -7[2] −2x−3y=−7

color(white)("XXXX")XXXXUsing [1] substitute (6x-11)(6x−11) for yy in [2]
"[3] " -2x - 18x+33 = -7[3] −2x−18x+33=−7
color(white)("XXXX")XXXXSimplifying
"[4] "20x = 40[4] 20x=40
"[5] "x = 2[5] x=2
color(white)("XXXX")XXXXUsing [5] substitute 44 for xx in [1]
"[6] "y = 12 -11[6] y=12−11
"[7] "y = 1[7] y=1

Solution is (x,y) = (2,1)(x,y)=(2,1)

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