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Question

What is the perimeter of a rectangle whose length is $7sqrt3+3sqrt5$ and whose width is $4sqrt3+2sqrt5$ ?

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Answer 1 · 2016-11-27T15:41:58

Perimeter is $22sqrt3+10sqrt5$

Perimeter of a rectangle is double the sum of its length and breadth.

In other words, if $l$ is length and $w$ is width then perimeter is

$2xx(l+w)$

Hence as length is $7sqrt3+3sqrt5$ and width is $4sqrt3+2sqrt5$

Perimeter is $2xx(7sqrt3+3sqrt5+4sqrt3+2sqrt5)$

= $2xx(11sqrt3+5sqrt5)$

= $22sqrt3+10sqrt5$