How do you solve using the completing the square method ${(x - 9)}^{2} = 1$ $(x-9)^2=1$ ?

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How do you solve using the completing the square method ${(x - 9)}^{2} = 1$ $(x-9)^2=1$ ?

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Answer 1 · 2016-07-30T18:05:13

If a number to the square is 1, that number is either 1 or -1

Explanation:

If ${(x - 9)}^{2} = 1$ $(x-9)^2=1$ , then $x - 9 = 1$ $x-9=1$ or $x - 9 = - 1$ $x-9=-1$ . Then is either $x = 9 + 1$ $x=9+1$ or $x = 9 - 1$ $x=9-1$ . The solutions are then $x = 10$ $x=10$ and $x = 8$ $x=8$

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How do you solve using the completing the square method ${(x - 9)}^{2} = 1$ $(x-9)^2=1$ ?

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Impact of this question

Science

Math

Humanities

... and beyond

How do you solve using the completing the square method (x−9)2=1(x-9)^2=1?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve using the completing the square method ${(x - 9)}^{2} = 1$ $(x-9)^2=1$ ?