How do you solve using the completing the square method $x (x - 2) = 5$ $x(x - 2) = 5$ ?

Question

How do you solve using the completing the square method $x (x - 2) = 5$ $x(x - 2) = 5$ ?

1 Answer

Impact of this question

1484 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-05T00:54:22

$x_{1} = 1 + \sqrt{6}$ $x_1=1+sqrt6$

$x_{2} = 1 - \sqrt{6}$ $x_2=1-sqrt6$

Explanation:

We start from the given equation

$x (x - 2) = 5$ $x(x-2)=5$

Expand it to make it a trinomial

$x^{2} - 2 x = 5$ $x^2-2x=5$

We add 1 to both sides of the equation. The number $1$ $1$ is derived from numerical coefficient of x which is $- 2$ $-2$ . Divide -2 by 2 then square the result which is 1.

$x^{2} - 2 x + 1 = 5 + 1$ $x^2-2x+1=5+1$

${(x - 1)}^{2} = 6$ $(x-1)^2=6$

Take the square root of both sides of the equation

$\sqrt{{(x - 1)}^{2}} = \pm \sqrt{6}$ $sqrt((x-1)^2)=+-sqrt6$

$x - 1 = \pm \sqrt{6}$ $x-1=+-sqrt6$

$x = + 1 \pm \sqrt{6}$ $x=+1+-sqrt6$

$x_{1} = 1 + \sqrt{6}$ $x_1=1+sqrt6$

$x_{2} = 1 - \sqrt{6}$ $x_2=1-sqrt6$

God bless....I hope the explanation is useful.

Science

Math

Humanities

... and beyond

How do you solve using the completing the square method $x (x - 2) = 5$ $x(x - 2) = 5$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve using the completing the square method x(x−2)=5 x(x - 2) = 5?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve using the completing the square method $x (x - 2) = 5$ $x(x - 2) = 5$ ?