How do you solve $v^2/25-1=11$ ?

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Answer 1 · 2016-10-30T12:06:46

$v$ is approximately $+-17.32$ or $+-sqrt(300)$

To solve for $v$ perform the following operations to keep the equation balanced while isolating $v$ :

$v^2/25 - 1 + 1 = 11 + 1$

$v^2/25 = 12$

$(v^2/25)25 = 12 * 25$

$V^2 = 300$

$sqrt(V^2) = +-sqrt(300)$

$v = +-17.32$

How do you solve v^2/25-1=11v^2/25-1=11?