How do you solve $v^2+7v+12=0$ ?

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Answer 1 · 2016-11-11T13:14:47

$v = -4$ and $v = -3$

$v^2 + 7v + 12 = 0$

$(v + 4)(v + 3) = 0$

Then solve for each term of the quadratic:

1)

$((v + 4)(v + 3))/(v + 3) = 0/(v + 3)$

$v + 4 = 0$

$v + 4 - 4 = 0 - 4$

$v = -4$

2)

$((v + 4)(v + 3))/(v + 4) = 0/(v + 4)$

$v + 3 = 0$

$v + 3 - 3 = 0 - 3$

$v = -3$

How do you solve v^2+7v+12=0v^2+7v+12=0?