How do you solve $(x-1)^2=9$ ?

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Answer 1 · 2018-03-17T03:57:33

$x=4,-2$

We have:

$(x-1)^2=9$

Taking the square root of both sides,

$sqrt((x-1)^2)=sqrt(9)$

$x-1=+-3$

$x=+-3+1$

$x=4,-2$

Answer 2 · 2018-03-17T04:01:06

$x=4$ & $x=-2$

We can start by taking the $+-$ square root of both sides. We get:

$x-1=+-3$

We can now break up our equation into the following:

$x-1=3$ & $x-1=-3$

We can solve the equations by adding $1$ to both sides yielding:

$x=4$ & $x=-2$

How do you solve (x-1)^2=9(x-1)^2=9?