How do you solve #|x - 2| = 1#?
1 Answer
Dec 21, 2016
The solution is
Explanation:
To clear the absolute-value bars, I must split the equation into its two possible two cases, one case for each sign:
#(x-2) = 1" "# or#" "-(x-2) = 1#
#x = 1+2" "# or#" " -x+2 = 1#
#x = 3" " " "# or#" " " " x=2-1=1#
Then the solutions are