How do you solve $x^2-10x=-24$ by graphing?

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Answer 1 · 2018-07-21T20:20:29

$x=4, x=6$

Well, you set it equal to $0$ :
$x^2-10x+24$

Graph it:
graph{x^2-10x+24 [-10, 10, -5, 5]}

Tips on determining the vertex:
$x=-b/(2a)$

For the y-coordinate, plug the x-coordinate into the equation and solve for $y$

Write the equation in the vertex form:
$y=a(x-h)^2+k$
Where $(h,k)$ is the vertex

$y=(x-5)^2-1$ , so essentially graph the parent quadratic function $y=x^2$ , 5 units to the right and one unit down

Look at the zeroes or x-intercepts:
$x=4 and 6$

How do you solve x^2-10x=-24x^2-10x=-24 by graphing?