How do you solve x^2-10x+25=0x2−10x+25=0 algebraically?

1 Answer
reudhreghs
Apr 1, 2016

x = 5x=5

Explanation:

Start off by writing the brackets (x + )(x +)(x+)(x+), because you know this will feature in the answer, given that there's an x^2x2.

Now you want to find two numbers that add together to make -10−10 and multiply together to make 2525. Use trial and error by writing down or thinking about the factors of 2525, and then which ones add to -10−10. You should come to -5−5 and -5−5.

This gives the brackets (x-5)(x-5)(x−5)(x−5) or (x-5)^2 = 0(x−5)2=0

Now change around the equation to make xx the subject.

(x-5)^2 = 0(x−5)2=0
x-5 = sqrt0x−5=√0
x-5 = 0x−5=0
x = 5x=5

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