How do you solve $x^2=121$ ?

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Answer 1 · 2018-03-10T16:14:49

$x1 = -11,$ $x2 = 11$

Move the constant to the left and change its sign

$x^2-121=0$

Using $a^2 - b^2 = (a - b) (a + b)$ , Factor the expression

$(x - 11)(x + 11)=0$

When the product of factors equals 0, at least one factor is 0

$x-11=0$

$x+11=0$

Solve both equations for $x$

$x=11$

$x=-11$

The final solutions are

$∴$ $x1=-11,$ $x2=11$

How do you solve x^2=121x^2=121?