How do you solve $x^2 - 12x + 36 = 49$ ?

Apr 23, 2016

$x=-1$
$x=13$

Given -

$x^2-12x+36=49$
$x^2-12x+36-49=0$
$x^2-12x-13=0$
$x^2+x-13x-13=0$
$x(x+1)-13(x+1)=0$
$(x+1)(x-13)=0$
$x=-1$
$x=13$

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How do you solve x^2 - 12x + 36 = 49x^2 - 12x + 36 = 49?