How do you solve $x^2-13x+36=0$ ?

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Answer 1 · 2016-03-31T00:30:29

$x_1=9$
$x_2=4$

Let us start from the given quadratic equation

$x^2-13x+36=0$
Solution by factoring

$(x-4)(x-9)=0$

Equate each factor to zero to solve for the roots

$x-4=0$
$x_1=4$

$x-9=0$
$x_2=9$

God bless...I hope the explanation is useful.

How do you solve x^2-13x+36=0x^2-13x+36=0?