How do you solve #x^2=13x-42#?

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Answer 1 · 2015-12-27T15:25:46

The roots of #x# are #7# and #6#

This equation may be written as

#x^2-13x+42=0#

or

#x^2-7x-6x+42 =0#

or

#x(x-7)-6(x-7)=0#

or

#(x-7)(x-6)=0#

So #x-7=0# or #x-6=0#

therefore #x=7# or #6#
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