How do you solve #x^2+14x=0 #?

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Answer 1 · 2016-04-17T17:48:59

The solutions are:
#x= 0#

#x = -14#

#x^2 + 14x = 0#

#x# is common to both the terms on the L.H.S of the expression:

#color(blue)(x) * ( x + 14 ) = 0#

Equating the factors to zero:

#color(blue)(x)= 0#

#x+ 14= 0 , x = -14#