How do you solve $x^{2} = 14 x + 5$ $x^2= 14x + 5$ ?

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How do you solve $x^{2} = 14 x + 5$ $x^2= 14x + 5$ ?

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Answer 1 · 2017-06-26T22:04:39

See below.

Explanation:

$x^{2} = 14 x + 5$ $x^2=14x+5$

$x^{2} - 14 x - 5 = 0$ $x^2-14x-5=0$

Since we cannot factor this, we must use the quadratic formula.

$x = \frac{14 \pm \sqrt{196 + 20}}{2} = \frac{14 \pm \sqrt{216}}{2} = \frac{14 \pm 6 \sqrt{6}}{2} = 7 \pm 3 \sqrt{6}$ $x=\frac(14\pm\sqrt(196+20))(2)=\frac(14\pm\sqrt(216))(2)=\frac(14\pm6\sqrt(6))(2)=7\pm3\sqrt(6)$

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How do you solve $x^{2} = 14 x + 5$ $x^2= 14x + 5$ ?

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