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How do you solve $x^{2} + 15 = 0$ $x^2 + 15 =0$ ?

1 Answer

Konstantinos Michailidis

Nov 7, 2015

In the set of real numbers, it does not have any solutions.

In the complex numbers it is

$x^{2} + 15 = 0 \Rightarrow x^{2} = 15 i^{2} \Rightarrow x = \pm \sqrt{15} i$ $x^2+15=0=>x^2=15i^2=>x=+-sqrt15i$

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