Question

How do you solve `x^2 + 16x + 48 = 0`?

Answer 1

-4 and - 12

Explanation:

`y = x^2 + 16x + 48 = 0`
Both roots are negative because ac > 0, and a and b have same sign (Rule of signs)
Factor pairs of (48) --> ... (-3, -16)(-4, -12). This sum is -16 = - b. Therefor, the 2 real roots are: - 4 and - 12