How do you solve $x^{2} - 16 x = - 64$ $x^2 - 16x = - 64$ ?

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Answer 1 · 2015-06-15T12:02:38

$x = 8$ $color(green)( x = 8$

$x^{2} - 16 x + 64 = 0$ $x^2-16x + 64 = 0$
We can first factorise this expression and then proceed towards finding the solution.

Factorising by splitting the middle term

$x^{2} - 16 x + 64 = x^{2} - 8 x - 8 x + 64$ $x^2-16x + 64 =x^2-8x - 8x + 64$

$x^{2} - 8 x - 8 x + 64 = x (x - 8) - 8 (x - 8)$ $x^2-8x - 8x + 64= x (x-8) - 8(x-8)$

$= (x - 8) (x - 8)$ $=color(green)((x-8)(x-8)$
So the solution for the expression will be:
$x - 8 = 0$ $x- 8 = 0$
$x = 8$ $color(green)( x = 8$

How do you solve x^2 - 16x = - 64 x2−16x=−64x^2 - 16x = - 64 ?