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How do you solve $x^{2} + 16 x = - 64$ $x^2 + 16x = -64$ ?

1 Answer

May 10, 2016

x = -8

Explanation:

$x^{2} + 16 x + 64 = 0$ $x^2 + 16x + 64 = 0$
${(x + 8)}^{2} = 0$ $(x + 8)^2 = 0$
Double root: x = -8

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