Question

How do you solve `(x + 2)^2 = 16`?

Answer 1

`x=2, -6`

Explanation:

`(x+2)^2=(+-4)^2`
`sqrt((x+2)^2)=sqrt (+-4^2)`
`x+2=+-4`
`x=2, -6`

Answer 2

`x=2 or x=-6`

Explanation:

`(x+2)^2=16`

`x+2=+-4`

`x=2 or x=-6`

Answer 3

`x=2`

Explanation:

`(x+2)^2=16`

Take the Square root of both sides

`rarrsqrt((x+2)^2)=sqrt16`

`rarrx+2=+-4`

`rarrx=+-4-2`

`rArrx=2, -6`

Check

`(2+2)^2=16`

`(4)^2=16`

`16=16` =)

~~~

`(2-6)^2=16`

`(-4)^2=16`

`16=16`