How do you solve $(x-2)^2=-3$ ?

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Answer 1 · 2016-08-11T17:09:34

$(1)$ : In $RR$ , the soln. set is $phi$ .

$(2)$ : $In CC$ , the soln set is ${2+-isqrt3 }.$

In $RR$ , the soln. set is $phi$ ; as, in $RR, (x-3)^2>=0$

In $CC$ since, $i=sqrt(-1)$ , we have, $(x-2)^2=-3=(isqrt3)^2$

$rArr x-2=+-isqrt3 rArr x=2+-isqrt3$

How do you solve (x-2)^2=-3(x-2)^2=-3?