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How do you solve ${(x - 2)}^{2} = - 3$ $(x-2)^2=-3$ ?

1 Answer

Jul 12, 2016

$(x - 2) = \pm \sqrt{- 3}$ $(x - 2) = +-sqrt(-3)$

$x = \emptyset$ $x = O/$

This equation has no real solutions. Hence, the solution set is ${\emptyset}$ ${O/}$ .

Hopefully this helps!

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