How do you solve $x^{2} - 2 = 7$ $x^2-2=7$ ?

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How do you solve $x^{2} - 2 = 7$ $x^2-2=7$ ?

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Answer 1 · 2016-11-03T20:48:45

$x = \pm 3$ $x=+-3$

Explanation:

The first step is to add 2 to both sides of the equation, thus isolating the $x^{2}$ $x^2$ term on the left side.

$x^2cancel(-2)cancel(+2)=7+2$

$rArrx^2=9$

Take the $color(blue)"square root "$ of both sides.

$sqrt(x^2)=+-sqrt9$

$rArrx=+-3$

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How do you solve $x^{2} - 2 = 7$ $x^2-2=7$ ?

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