How do you solve $x^{2} - 2 x = 0$ $x^2-2x=0$ ?

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Answer 1 · 2016-02-14T18:22:46

$x = 0 or x = 2$ $x=0orx=2$

First factorize to get

$x (x - 2) = 0$ $x(x-2)=0$

Hence, either $x = 0 or (x - 2) = 0$ $x=0 or (x-2)=0$

$therefore x=0 or x=2$ .

How do you solve x^2-2x=0 x2−2x=0x^2-2x=0 ?