Question

How do you solve `-x^2+2x-1=0`?

Answer 1

x=1

Explanation:

IT IS EASY!!
`-x^2+2x-1=0` { * COMPARING WITH *
`ax^2+bx+c`
** we see **
`a=-1,b=2,c=-1`
by splitting the middle term....
* WE GET,
PRODUCT=`ca = -1*-1=1`
SUM = `2` *
therefore
`-x^2+x+x-1=0`
`-x(x-1)+(x-1)=0`
`(-x+1)(x-1)=0`
hence
x=1................................. hope u get it
** * CHEERS !!:D * **

Answer 2

`x=1`.

Explanation:

This equation can be solved by factorization.

`-x^2 + 2x - 1 = 0`

`-1(x^2 -2x + 1) = 0`

`x^2 -2x + 1 = 0`

`x^2 - x - x + 1 =0`

`x( x-1 ) -1( x-1 ) =0`

`( x-1 )( x-1 ) = 0`

Now,
`x-1 = 0`

Therefore, `x=1`.