How do you solve $x^{2} + 2 x + 1 = 0$ $x^2 + 2x + 1 = 0$ ?

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Answer 1 · 2016-01-27T11:06:53

See explanation.

$x^{2} + 2 x + 1 = {(x + 1)}^{2}$ $x^2 + 2x + 1 = (x+1)^2$

This represents the equation for a right way up parabola touching the $x$ $x$ -axis at $x = - 1$ $x=-1$ . The $y$ $y$ -intercept is $+ 1$ $+1$

graph{x^2 + 2x + 1 [-10, 10, -5, 5]}

How do you solve x^2 + 2x + 1 = 0x2+2x+1=0 x^2 + 2x + 1 = 0?