Question

How do you solve `x^2 + 2x + 13 = -8`?

Answer 1

See below.

Explanation:

Adding `8` to both sides,

`x^2 + 2x + 21=0`

Let's use the quadratic formula, as factoring will not work in this case.

`x=\frac(-2\pm\sqrt(2^2-4(1)(21)))(2)=\frac(-2\pm\sqrt(-80))(2)=\frac(-2\pm4\sqrt(-5))(2)=\frac(-2\pm4i\sqrt(5))(2)=-1\pm2i\sqrt5`