How do you solve $x ^2 + 2x - 22 = 0$ ?

Question

2239 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-04T10:28:43

3.796 and -5.796

Compute $(b^2)-(4*a*c)$ first which is delta. b is 2 and c is -22 (a is 1 in this equation).
You will get delta as 92.

$x=(-b+sqrt92)/2=3.796$ the first x
$x=(-b-sqrt92)/2=-5.796$ the second x

How do you solve x ^2 + 2x - 22 = 0x ^2 + 2x - 22 = 0?