How do you solve $x^2 + 2x - 3 = 0$ ?

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Answer 1 · 2018-04-04T17:55:38

$x = -3$ , $x = 1$

Here's how I did it:

To solve for $x$ , we factor it.
To factor this, you have to find two numbers that multiply up to $-3$ and add up to $2$ .

These two numbers are $3$ and $-1$ :
$3 * -1 = -3$
$3 - 1 = 2$

Now we put the equation like this:
$(x+3)(x-1) = 0$

$x+3 = 0 -> x = -3$

$x - 1 = 0 -> x = 1$

How do you solve x^2 + 2x - 3 = 0 x^2 + 2x - 3 = 0?