How do you solve $x^2+2x-3=0$ graphically?

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Answer 1 · 2016-03-08T08:51:19

Find the points at which the parabola $y=x^2+2x-3$ cuts the x-axis y = 0.-

$(x+1)^2=y+4$
The axis of this parabola is $x=-1$
The vertex is $(-1, -4)$ ,
The parabola cuts the x-axis y = 0 at x = 1 and $x = -3$ .

How do you solve x^2+2x-3=0x^2+2x-3=0 graphically?