How do you solve $-x ^ { 2} + 2x + 3= x ^ { 2} - 2x + 3$ ?

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Answer 1 · 2017-03-10T03:40:22

The answers are $0$ or $2$ .

$-x^2 + 2x+3= x^2 - 2x+3$

$=> -x^2+2x+3-x^2+2x-3=0$

$=> -2x^2+4x=0$

$=> 2x^2-4x=0$

$=> x^2-2x=0$

$=> x(x-2)=0$

Hence, $x$ is either $2$ or $0$ .

How do you solve -x ^ { 2} + 2x + 3= x ^ { 2} - 2x + 3-x ^ { 2} + 2x + 3= x ^ { 2} - 2x + 3?