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How do you solve $x^{2} - 32 = 112$ $x^2-32=112$ ?

1 Answer

Jul 6, 2016

$x = \pm 12$ $x=+-12$ .

Explanation:

$x^{2} - 32 = 112$ $x^2-32=112$

rArr x^2=32+112=144#

$\Rightarrow x = \sqrt{144} = \pm 12$ $rArr x=sqrt144=+-12$

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