How do you solve x^2+3x+1=0x2+3x+1=0 algebraically?

1 Answer
Binayaka C.
Nov 7, 2016

x=(-3+sqrt5)/2 orx=(-3-sqrt5)/2x=−3+√52orx=−3−√52

Explanation:

x^2+3x+1=0 or x^2+3x+9/4 -9/4+1=0 or (x+3/2)^2 -5/4=0 or (x+3/2)^2 =5/4 or x+3/2 = +-sqrt5/2 or x= -3/2+-sqrt5/2 :. x=(-3+sqrt5)/2 orx=(-3-sqrt5)/2 {Ans]

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