How do you solve x^2 - 3x - 10 = 0 ? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer George C. Jun 14, 2015 x^2-3x-10 = (x-5)(x+2) So x^2-3x-10=0 has roots x=5 and x=-2. Explanation: If x^2-3x-10 = (x-a)(x+b) = x^2-(a-b)x-ab then a*b = 10 and a-b=3. That is satisfied by a=5 and b=2. Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 20083 views around the world You can reuse this answer Creative Commons License