How do you solve $x^{2} - 3 x - 10 = 0$ $x^2-3x-10=0$ ?

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Answer 1 · 2015-12-15T09:00:37

$Solution Set = {5, - 2}$ $"Solution Set"={5,-2}$

$\times x^{2} - 3 x - 10 = (x - 5) (x + 2)$ $color(white)(xx)x^2-3x-10=(x-5)(x+2)$

For $x - 5 = 0$ $x-5=0$ ,
$\Rightarrow x_{1} = 5$ $=>color(red)(x_1=5)$

For $x + 2 = 0$ $x+2=0$ ,
$\Rightarrow x_{2} = - 2$ $=>color(red)(x_2=-2)$

$Solution Set = {5, - 2}$ $"Solution Set"={5,-2}$

How do you solve x^2-3x-10=0x2−3x−10=0x^2-3x-10=0?