How do you solve $x^2 + 3x -2=0$ ?

Question

1362 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-06T00:55:37

$x^2+3x-2=0$ is a quadratic equation in the form $ax^2+bx-2=0$ where $a=1$ , $b=3$ , and $c=-2$ .

To solve this equation we can use the quadratic formula.

$x=(-b+-sqrt(b^2-4ac))/(2a)$

Plug the given values into the formula.

$x=(-3+-sqrt(3^2-4*1*-2))/(2*1)$

$x=(-3+-sqrt(9+8))/2$

$x=(-3+-sqrt17)/2$

$x=(-3+sqrt17)/2, (-3-sqrt17)/2$

How do you solve x^2 + 3x -2=0x^2 + 3x -2=0?