Question

How do you solve `x^2 - 3x - 23 = 5`?

Answer 1

Solve `y = x^2 - 3x - 23 = 5`

Ans: -4 and 7

Explanation:

`y = x^2 - 3x - 28 = 0`
Find 2 numbers p and q, knowing sum (-b = 3) and product (c = -28).
p and q have opposite signs. (Rule of sign).
Factor pairs of (-28) --> (-2, 14)(-4, 7). This sum is 3 = -b.
Then, the 2 real roots are : `-4` and `7.`