How do you solve $x^2+3x-4=0$ graphically?

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Answer 1 · 2017-08-30T14:10:27

See below.

Plot the points generated by the function $y = x^2 + 3x -4$ .

Where the parabola crosses or turns at the $x$ axis is the solution to the equation $x^2 + 3x -4 = 0$ .

In this example the parabola crosses the $x$ axis at the points $x = -4$ and $x = 1$ , so this is the solution to the equation.
See graph:

graph{x^2 +3x -4 [-16.02, 16.01, -8.01, 8.01]}

How do you solve x^2+3x-4=0x^2+3x-4=0 graphically?