How do you solve $x^2 - 3x = -6x - 1$ ?

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Answer 1 · 2015-08-02T06:39:28

The solutions for the expression are
$color(green)(x=(-3-sqrt5)/2, x=(-3+sqrt5)/2$

$x^2−3x=−6x−1$

$x^2−3x+6x+1=0$

$x^2+3x+1=0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=1, b=3, c=1$

The Discriminant is given by:
$Delta=b^2-4*a*c$
$= (3)^2-(4*(1)*1)$
$= 9-4=5$

As $Delta>0$ there are two solutions.

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = ((-3)+-sqrt(5))/(2*1) = (-3+-sqrt(5))/2$

The solutions for the expression are:
$color(green)(x=(-3-sqrt5)/2, x=(-3+sqrt5)/2$

How do you solve x^2 - 3x = -6x - 1x^2 - 3x = -6x - 1?